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0=x^2-11x-1
We move all terms to the left:
0-(x^2-11x-1)=0
We add all the numbers together, and all the variables
-(x^2-11x-1)=0
We get rid of parentheses
-x^2+11x+1=0
We add all the numbers together, and all the variables
-1x^2+11x+1=0
a = -1; b = 11; c = +1;
Δ = b2-4ac
Δ = 112-4·(-1)·1
Δ = 125
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{125}=\sqrt{25*5}=\sqrt{25}*\sqrt{5}=5\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-5\sqrt{5}}{2*-1}=\frac{-11-5\sqrt{5}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+5\sqrt{5}}{2*-1}=\frac{-11+5\sqrt{5}}{-2} $
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